![]() ![]() I do not think it makes much of a difference in practice.Īs for efficiency, an electrical water heater can convert electricity with almost 100% efficiency to heat that can be transferred to the water. And as always, double check with some other source and my help is without any guarantee or similar. And for testing/sampling the cool-down, measure a larger drop in temperature, such as 10f, else the result will be unreliable (reading 1f or 2f changes off a small thermometer may be very inaccurate). Also, you should have some extra power available, just to be sure. That’s just an example, I have no idea how fast a tub cools down. If you use a 611 watts heater in this example, then it will be about enough to reverse this cool-down from 105f to 103f by heating the water back up from 103f to 105f during the same period (realistically, of course, the water does not cool down, but stays at the same temperature). ![]() Using the “Water Heating Power Calculator” above (250 us gallons, start temperature 103f, end temperature 105f, 120min) tells us that a heating power of 611 watts is required. Let’s make a calculation example for a tub with 250 us gallons that cools down from 105f to 103f in 2 hours. If you can test how fast the water cools down in your tub, then you can calculate how much heating power is required to prevent that from happening. ![]() It very much depends on the surrounding temperature, the heat conductivity of your hot tub material, and the shape of the tub.īut I have an idea. That is impossible to calculate with the information given. ![]()
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